Evaluate: `int(3x+1)\ sqrt(4-3x-2x^2)\ dx`

Explanation

To evaluate the integral \( I = \int (3x + 1) \sqrt{4 - 3x - 2x^2} \, dx \), we can follow these steps:

### Step 1: Rewrite the Integral
We start with the integral:
\[ I = \int (3x + 1) \sqrt{4 - 3x - 2x^2} \, dx \]

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