Evaluate: `int1/(sinx-sin2x)dx`

Explanation

`I=int frac{1}{sin x-sin 2 x} d x `


`text { or } I=int frac{d x}{sin x-2 sin x cos x} `


`text { or } I=int frac{d x}{sin x(1-2 cos x)} `


`text { or } I=int frac{sin x}{sin ^{2} x(1-2 cos x)} d x `


`text { or } I=int frac{sin x d x}{(1-cos ^{2} x)(1-2 cos x)}`



Putting, `cos x=t` or `-sin x d x=d t`


or `sin x d x=-d t`, we get


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