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Evaluate: int(x^2+6x-8)/(x^3-4x)dx...

Evaluate: `int(x^2+6x-8)/(x^3-4x)dx`

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`I=int(frac{x^{2}+6 x-8}{x^{3}-4 x}) d x`
`=int frac{(x^{2}+6 x-8)}{x(x^{2}-4)} d x`
`=int frac{(x^{2}+6 x-8)}{x(x-2)(x+2)} d x`
Let `frac{x^{2}+6 x-8}{x(x-2)(x+2)}=frac{A}{x}+frac{B}{x-2}+frac{C}{x+2}`
`Rightarrow frac{x^{2}+6 x-8}{x(x-2)(x+2)}=frac{A(x-2)(x+2)+B(x)(x+2)+C(x)(x-2)}{x(x-2)(x+2)}`
`Rightarrow x^{2}+6 x-8=A(x^{2}-4)+B(x^{2}+2 x)+C(x^{2}-2 x)`
Putting `x-2=0`
`Rightarrow x=2`
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