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Write a value of inte^(logsinx)cosx\ dx...

Write a value of `inte^(logsinx)cosx\ dx`

Text Solution

Verified by Experts

Let,
`sin x=t`
`cos x dx=dt`
`=inte^(logsinx)cosx\ dx`
`=inte^(log t)dt`
`=int tdt`
`=(t^2)/(2)+C`
`=(sin^2 x)/(2)+C`
...
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