Write a value of `inta^x\ e^x\ dx`

Explanation

Solution:

I=`\int a^{x} e^{x} d x`

Let `t=a e`

I=`\int t^{x} d x`

We know that `\int a^{x} d x=\frac{1}{\log a} a^{x}+c`

I=`\frac{1}{\log t} t^{x}+c`

I=`\frac{1}{\log a e}(a e)^{x}+c \quad \ldots \ldots \ where .... t=a e`