Write a value of `int(e^(x(log)_e a)+e^(a(log)_e x))\ dx`

Explanation

Solution:

`(e^{x \log e^{a}}+e^{a \log _{e} x}) d x`

`\int(e^{\log a}+e^{\log x}) d x`

=`\int(a^{x}+x^{a}) d x`

=`\frac{a^{x}}{\log a}+\frac{x^{a+1}}{a+1}+C`