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intx^(sinx) ((sinx)/x+cosxdotlogx) dx is...

`intx^(sinx) ((sinx)/x+cosxdotlogx) dx` is equal to (A) `x^(sinx)+C` (B) `x^(sinx)cosx+C` (C) `((x^(sinx))^2)/2+C` (D) none of these

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Let` u=x^sinx⇒logu=sinxlogx`
⇒`1/u​du=sinx/x​+cosxlogxdx`
⇒`du=u(sinx/x​+cosxlogx)dx`
⇒`du=x^sinx(sinx/x​+cosxlogx)dx`
...
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