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int1/(1+tanx)\ dx=...

`int1/(1+tanx)\ dx=` `

Text Solution

Verified by Experts

`I=∫(1)/(1+tanx)​dx`
Put,
`t=tanx`
`dt=sec^2xdx`
`dt=(1+tan^2x)dx`
Therefore,
`I=∫(1)/((t+1)(t^2+1))​dt`
...
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