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int(x+3)/((x+4)^2)e^x\ dx= (e^x)/(x+4)+...

`int(x+3)/((x+4)^2)e^x\ dx=` `(e^x)/(x+4)+C` (b) `(e^x)/(x+3)+C` (c) `1/((x+4)^2)+C` (d) `(e^x)/((x+4)^2)+C`

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Given,`int(x+3)/((x+4)^2)e^x\ dx`
=`int(x+3-1+1)/((x+4)^2)e^x\ dx`
=`∫e^x[(x+4)/(x+4)^2​−1/(x+4)^2​]dx`
=`∫e^x[1/(x+4)​−1/(x+4)^2​]dx`
Now, `∫e^x(f(x)+f′(x))dx=e^xf(x)`
∴`I=e^x/(x+4)​`
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