Evaluate: `intxsin^5x^2cosx^2\ dx`

Explanation

Given,

I=: `intxsin^5x^2cosx^2\ dx`

let `sinx^2=t`

`2xcosx^2dx=dt`

thus,

`I=int (t^5dt)/2`

`I=t^6/(12)+C`

`I=(sinx^2)^6/(12)+C`