`intsqrt(sinx)cos^3xdx`

Explanation

I=`intsqrt(sinx)cos^3xdx`

I=`intsqrt(sinx)cos^2xcosxdx`

I=`intsqrt(sinx)(1-sin^2x)cosxdx`


let `sinx=t`

`cosxdx=dt`

So,

`I=int sqrt(t)(1-t^2)dt`

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