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int1/(3x^2+13x-10)dx...

`int1/(3x^2+13x-10)dx`

Text Solution

Verified by Experts

Given,
`3x^2+13x-10 `
`= 3x^2+15x-2x-10 `
`= 3x(x+5)-2(x-5) `
`= (x-5) (3x-2)`
Thus,
`int1/(3x^2+13x-10)dx`=`A/(x+5)+B/(3x-2)`
Solving we get `A=-1/(17)` and `B=3/(17)`
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