Evaluate: `int1/(sqrt(3-2x-x^2))\ dx`

Explanation

To evaluate the integral \( I = \int \frac{1}{\sqrt{3 - 2x - x^2}} \, dx \), we will follow these steps:

### Step 1: Rewrite the expression under the square root
First, we need to rewrite the expression \( 3 - 2x - x^2 \) in a more manageable form. We can rearrange it as follows:

\[ 3 - 2x - x^2 = - (x^2 + 2x - 3) \]
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