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Evaluate: intsqrt(3x^2+4x+1)\ dx...

Evaluate: `intsqrt(3x^2+4x+1)\ dx`

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To evaluate the integral \( \int \sqrt{3x^2 + 4x + 1} \, dx \), we will follow these steps: ### Step 1: Factor out the coefficient of \( x^2 \) First, we notice that the expression inside the square root has a coefficient of 3 for \( x^2 \). We can factor this out: \[ \int \sqrt{3} \sqrt{x^2 + \frac{4}{3}x + \frac{1}{3}} \, dx \] ...
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intsqrt(x^(2)+4x+1)dx