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intlog(x+sqrt(a^2+x^2))dx...

`intlog(x+sqrt(a^2+x^2))dx`

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We have given
`intlog(x+sqrt(a^2+x^2))dx`
`I=intlog(x+sqrt(a^2+x^2))dx`
`I=int1.log(x+sqrt(a^2+x^2))dx`
`I=log(x+sqrt(a^2+x^2))int 1dx-int [d/(dx)(log(x+sqrt(a^2+x^2))) int 1dx]dx`
`I=log(x+sqrt(a^2+x^2)).x-int (1/(x+sqrt(x^2+a^2)))xx(1+(1xx2x)/(2sqrt(x^2+a^2))).xdx`
`I=log(x+sqrt(a^2+x^2)).x-int (x)/(sqrt(x^2+a^2))dx`
Let x^2+a^2=t In integral
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