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Evaluate: int1^2(logx)/(x^2)dx...

Evaluate: `int_1^2(logx)/(x^2)dx`

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To evaluate the integral \( \int_1^2 \frac{\log x}{x^2} \, dx \), we will use integration by parts. ### Step 1: Choose \( u \) and \( dv \) Let: - \( u = \log x \) (which implies \( du = \frac{1}{x} \, dx \)) - \( dv = \frac{1}{x^2} \, dx \) (which implies \( v = -\frac{1}{x} \)) ### Step 2: Apply the Integration by Parts Formula ...
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