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Evaluate: int0^(pi//2)xsinx\ dx...

Evaluate: `int_0^(pi//2)xsinx\ dx`

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`int_(0)^(pi//2)x sin xdx=[x int sin x dx]_(0)^(pi//2)-int_(0)^(pi//2)[(d)/(dx)(x)int sin x dx]dx`
`=[x(-cosx)]_(0)^(pi//2)-int_(0)^(pi//2)1.(-cosx)dx`
`=-[x cos x]_(0)^(pi//2)+int_(0)^(pi//2)cos x dx`
`=-[(pi)/(2)cos.(pi)/(2)-0]+[sinx]_(0)^(pi//2)`
`=0+(sin.(pi)/(2)-sin0)`
`=1.`
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