Evaluate the following definite integral: `int_0^1(1-x)/(1+x)dx`

Explanation

consider,` I=\int_{0}^{1} \frac{1-x}{1+x} d x`


`=\int_{0}^{1} \frac{2-(1+x)}{1+x} d x `



`=\int_{0}^{1} (\frac{2}{1+x}-1) d x `


`=[2 \log (x+1)-x]_{0}^{1} `
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