Evaluate the following definite integral: `int_1^2((x-1)/(x^2))e^x dx`

Explanation

`int_{1}^{2}(frac{x-1}{x^{2}}) e^{pi} d x`
`
int_{1}^{2} frac{e^{(x-1)}}{x^{2}} d x`
`
frac{-e^{x}(x-1)}{x} mid 1-int_{1}^{2}-e^{x} d x `
` Rightarrow u=e^{x}(x-1) ; v^{1}=frac{1}{x^{2}}`
`
frac{-e^{x}(x-1)}{x}+.e^{x}|_{1} ^{2}`
`
frac{-e^{2}(2-1)}{2}+e^{2}-frac{e^{1}(1-1)}{1}+e^{1}`
`
{[frac{-e^{2}}{2}+e^{2}-e] }`