Evaluate : `int_e^(e^2){1/(logx)-1/((logx)^2)}dx`

Explanation

Take, `I=int[frac{1}{log x}-frac{1}{(log x)^{2}}] d x`

Take `log x=t`
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therefore {x}={e}^{{t}} `
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therefore {dx}={e}^{{t}} {dt} `
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therefore {I}=int {e}^{{t}}[frac{1}{{t}}-frac{1}{{t}^{2}}] {dt}`


Take` f(t)=frac{1}{t}`
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