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Evaluate: int0^(pi//2)sqrt(costheta)sin^...

Evaluate: `int_0^(pi//2)sqrt(costheta)sin^3theta`d`theta`

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To evaluate the integral \( I = \int_0^{\frac{\pi}{2}} \sqrt{\cos \theta} \sin^3 \theta \, d\theta \), we can follow these steps: ### Step 1: Rewrite the integral We can express \( \sin^3 \theta \) in terms of \( \sin^2 \theta \): \[ I = \int_0^{\frac{\pi}{2}} \sqrt{\cos \theta} \sin^2 \theta \sin \theta \, d\theta \] Using the identity \( \sin^2 \theta = 1 - \cos^2 \theta \), we rewrite the integral: ...
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Knowledge Check

  • int_(0)^((pi)/(2))sqrt(costheta)*sin^(3)theta d theta= . . .

    A
    `(-20)/(21)`
    B
    `(-8)/(21)`
    C
    `(20)/(21)`
    D
    `(8)/(21)`
  • The value of int_(0)^(pi//2) sqrt( sin 2 theta) sin theta d theta is

    A
    `1`
    B
    `0`
    C
    `pi//2`
    D
    `pi//4`
  • int(sqrt(cos2 theta))/(sin theta)d theta=

    A
    `log|cot theta + sqrt(cot^2 theta-1)|+sqrt(2) log|cos theta+sqrt(cos^2theta-(1)/(2))|+c`
    B
    `-log|cot theta + sqrt(cot^2 theta-1)|+sqrt(2) log|cos theta+sqrt(cos^2theta-(1)/(2))|+c`
    C
    `log|cot theta + sqrt(cot^2 theta-1)|-sqrt(2) log|cos theta+sqrt(cos^2theta-(1)/(2))|+c`
    D
    `-log|cot theta + sqrt(cot^2 theta-1)|-sqrt(2) log|cos theta+sqrt(cos^2theta-(1)/(2))|+c`
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