Evaluate the following integral: `int_0^1(sqrt(tan^(-1)x))/(1+x^2)dx`

Explanation

To evaluate the integral

\[ I = \int_0^1 \frac{\sqrt{\tan^{-1} x}}{1+x^2} \, dx, \]

we will use the substitution \( t = \tan^{-1} x \).

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