Evaluate the following integral: `int_(-pi//2)^(pi//2)|sinx+"cosx|dx`

Explanation

I=`int_(-pi//2)^(pi//2)|sinx+"cosx|dx`

I=`int_(-pi//2)^(pi//2)(sinx+"cosx)dx`

`I=(-cosx-sinx)
_(-pi//2)^(pi//2)`

=`−[cos(π/2)​−cos0]−[sin(π/2)​−sin0]`

=`−[0−1]−[1−0]`

=`1−1=0.`