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Evaluate: int(-pi//2)^(pi//2)sin^2x\ dx...

Evaluate: `int_(-pi//2)^(pi//2)sin^2x\ dx`

Text Solution

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`int_(-pi/2)^(pi/2)frac{1-cos2x}{2}dx`
`=[x/2 - (sin2x)/4]_(-pi/2)^(pi/2)`
`=pi/2`
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