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From the mixture of 4 moles Ca(3)(PO(4))...

From the mixture of 4 moles `Ca_(3)(PO_(4))_(2)` and 5 moles of `P_(4) O_(10)` and 6 moles of `H_(3)PO_(3)` all the phosphorus atoms are removed then moles of `P_(4)` molecule formed from all these atoms is

A

`8.5`

B

17

C

34

D

10

Text Solution

Verified by Experts

The correct Answer is:
A
Moles of P atom in `Ca_(3)(PO_(4))_(2)=4xx2=8`
Moles of P atom in `P_(4)O_(10)=5xx4=20`
Moles of P atom in `H_(3)PO_(3)=6xx1=6`
total moles of `p-` atoms `=34`
`:. " " ` no. of moles of `P_(4)` molecules `=(34)/(4)=8.5`
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