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Equivalent weight of KHC(2)O(4).3NaHC(2)...

Equivalent weight of `KHC_(2)O_(4).3NaHC_(2)O_(4)` in reaction with acidic `KMnO_(4)` is `(M=` Molar mass )

A

`(M)/(8)`

B

`(M)/(4)`

C

`M`

D

`(M)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
1
`KHC_(2)underset(v.f)underset(darr)(O_(4)).3NaHC_(2)O_(4)`
`v.f=2xx3=6'`
over all `v.f=6+2=8`
`=E=(M)/(v.f)=(M)/(8)`
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