If the density of water is 1 g `cm^(-3)` then the volume occupied by one molecule of water is approximately

Options

A. `3xx10^(-23)mL`
B. `6xx10^(-22)mL`
C. `3xx10^(-21)mL`
D. `9xx10^(-23)mL`

Answer

1

Explanation

`1xx10^(3)kg//m^(3)=1g//mL=1gm//c c" " [` Since ,`1m^(3)=10^(6)cm^(3)=10^(6)mL]`
`6.022xx10^(23)H_(2)O` molecule weight `rarr 18g`
`1H_(2)O` molecule weight `rarr (18)/(6.022xx10^(23))g=3xx10^(-23)g`
`d=(mass)/(volume)," "` So, volume`=(3xx10^(-23))/(1(g//mL))=3xx10^(-23)mL`