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In the section :Na(2)S(2)O(3)+4Cl(2)+5H(...

In the section `:Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`.
the equivalent weight of `Na_(2)S_(2)O_(3)` will be : `(M=` molecular weight of `Na_(2)S_(2)O_(3)`)

A

`M//4`

B

`M//8`

C

`M//1`

D

`M//2`

Text Solution

Verified by Experts

The correct Answer is:
2
`Na_(2)overset(+2)(S)_(2)o_(3)rarr Na_(2)overset(+6)(S)O_(4)`
the total change in oxidation number `=4xx2=8`
`:. " "E_(Na_(2)S_(2)O_(3))=(mol.wt.)/(V.f)=(M)/(8)`
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