According to Bohr's model, if the kinetic energy of an electron in `2^(nd)` orbit of `He^(+)` is `x`, then what should be the ionisation energy of the electron revolving in `3rd` orbit of `M^(5+)` ion

Options

A. `x`
B. `4x`
C. `x//4`
D. `2x`

Answer

2

Explanation

`(K.E_(1))/(K.E_(2))=(Z_(1)^(2)xxn_(2)^(2))/(n_(1)^(2)xxZ_(2)^(2))" "or" "(x)/(K.E_(2))=(2^(2)xx3^(2))/(2^(2)xx6^(2))`
`:." " K.E_(2)=4xx(Z` for `M^(5+)=6` as it is `H-` like species ] Now, `" "K.E.=-T.E.`
`:. " "T.E.=-4x" "` and` " "I.E.=-T.E.=-(4x)=+4x`