In the emission spectrum of `H-` atom from energy level `'n'` to ground state in one more step, no line belonging to the Brackett series is observed. The wave number of lines belonging to Balmer series may be

Options

A. `(8R)/(9),(5R)/(36)`
B. `(3R)/(16),(8R)/(9)`
C. `(5R)/(36),(3R)/(16)`
D. `(3R)/(4),(3R)/(16)`

Answer

3

Explanation

Possible transition are
`3 rarr 2 " "&" "4 rarr 2`
`bar(v)=Rz^(2)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
`vec(v)_(3rarr2)=Rxx1[(1)/(4)-(1)/(9)]=(5R)/(36)`and`bar(v)_(4rarr2)=Rxx1[(1)/(4)-(1)/(16)]=(3R)/(16)Ans.`