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If Photon having wavelength 6.2nmwas all...

If Photon having wavelength `6.2nm`was allowed to strike a metal plate having work function `50eV` then calculate wavelength associated with emitted electron `:`

A

`1xx10^(-10)m`

B

`2xx10^(-10)m`

C

`3xx10^(-18)m`

D

`4xx10^(-34)m`

Text Solution

Verified by Experts

The correct Answer is:
1
`KE_(max)=hv-w=(1240)/(6.2)-50=150eV`
`lambda_(deBroglie)=sqrt((150)/(KE_(max)i n eV))A=sqrt((150)/(150))=1A`
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