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The ratio of magnetic moments of Fe(III)...

The ratio of magnetic moments of `Fe(III)` and `Co(II)` is `:`

A

`sqrt(5):sqrt(7)`

B

`sqrt(35):sqrt(15)`

C

`7:3`

D

`sqrt(24):sqrt(15)`

Text Solution

Verified by Experts

The correct Answer is:
2
`Fe(III)[Ar]3d^(5),` unpaired electron`=5,` magnetic moment `=sqrt(5(5+2))BM`
`CO(II)-[Ar]3d^(7),` unpaired electrons `=3,` magnetic moment `=sqrt(3xx(3+2))BM`
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