According to Bohr's theory, the ratio of electrostatic force of attraction acting on electron `3^(rd)` orbit of `He^(+)` ion and `2^(nd)` orbit of `Li^(2+)` ion is `((3)/(2))^(x)`. Then, the value of `x` is `:`

Options

A. 7
B. -6
C. 6
D. -7

Answer

4

Explanation

Electrostatic force of attraction `Fprop (Z^(3))/(n^(4))`
`:. ((F_(n=3))_(He^(+)))/((F_(n=2))_(Li^(2+)))=(2^(3)//3^(4))/(3^(3)//2^(4))=((2)/(3))^(7)=((3)/(2))^(-7)" ":.x=-7" "F=(KZe^(2))/(R^(2))`