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If the wavelength of photon emitted from...

If the wavelength of photon emitted from an electron jump `n=4` to `n=2` in a `H-` like species is `1216 Å` then the species is `:`

A

`H-` atom

B

`He^(+)` ion

C

`Li^(2+)`ion

D

`Be^(3+)`ion

Text Solution

Verified by Experts

The correct Answer is:
2
Energy of photon `=(124000)/(1216)=10.2eV=(H)_(2+1)=(He^(+))_(4rarr2)`
so, species is `He^(+)` ion
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