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There are 6.02 xx 10^(22) molecules each...

There are `6.02 xx 10^(22)` molecules each of `N_(2),O_(2)` and `H_(2)` which are mixed together at `760 mm` and `273 K`. The mass of the mixture in grams is `:`

A

`6.2`

B

`4.12`

C

`3.09`

D

7

Text Solution

Verified by Experts

The correct Answer is:
1
Moles of each gas `=(6.02xx10^(22))/(N_(A))=0.1`
So mass of mixture `=0.1xxM_(N_(2))+0.1xxM_(O_(2))+0.1xxM_(H_(2))`
`=0.1xx28+0.1xx32+0.1xx2=6.2 ` grams.
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