At what temperature will hydrogen molecules have the same root mean square speed as nitrogen molecules at `27^(@)C` ?

Options

A. `21.43^(@)C`
B. `42.86K`
C. `21.43K`
D. `42.86^(@)C`

Answer

3

Explanation

`sqrt((3RT)/(M_(N)))=sqrt((3Rxx300)/(M_(N)))`
`(T)/(M_(H))=(300)/(M_(N))" "(T)/(2)=(300)/(28)" "T=21.43`