The compressibility factor for nitrogen at `330K` and `800 atm` is `1.90` and at `570K` and `200 atm` is `1.10`. A certain mass of `N_(2)` occupies a volume of `1dm^(3)` at `330K` and `800 atm` calculate volume occupied by same quantity of `N_(2)` gas at `570 K` and `200 atm`

Options

A. `1L`
B. `2 L`
C. `3L`
D. `4L`

Answer

4

Explanation

`Z=(PV)/(nRT),1.90=(1xx800)/(nxxRxx330)`
`n=(1xx800)/(1.90xxRxx330)`
`z=1.10=(Vxx200)/(nxxRxx570)`
`1.10=(Vxx200xx1.90xxRxx330)/(800xxRxx570)`
`V=4L`