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A gaseous mixture containing He,CH(4) an...

A gaseous mixture containing `He,CH_(4)` and `SO_(2)` was allowed was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially ? If mixture contain `He, CH_(4)` and `SO _(2)` in `1:2:3` mole ratio.

A

`2:2:3`

B

`6:6:1`

C

`sqrt(2):sqrt(2):3`

D

`4:4:3`

Text Solution

Verified by Experts

The correct Answer is:
4

`(n'_(He))/(n'_(CH_(4)))=(1)/(2)sqrt((16)/(4))=(1)/(1)`
`(n'_(He))/(n'_(SO_(2)))=(1)/(3)sqrt((64)/(3))=(4)/(3)`
`n'_(He):n'_(CH_(4)):n'_(SO_(2))=4:4:3`
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