Two flask A and B of equal volumes main...

Two flask A and B of equal volumes maintained at temperature `300K` and `700K` contain equal mass of `He(g)` and `N_(2)(g)` respectively. What is the ratio of total translational kinetic energy of gas in flask A to that of flask B ?

`1:3`

`3:1`

`3:49`

None of these

Text Solution

Verified by Experts

The correct Answer is:

Moles ratio `= (n_(He))/(n_(H_(2)))=(w//4)/(w//28)=(7)/(1)`
Ratio of translational `K.E.=(n_(He).T_(He))/(n_(N_(2)).T_(N_(2)))=(7)/(1)xx(300)/(700)=3:1`

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