`CaCO_(3)(s) hArrCaO(s)+CO_(2)(g)` At equilibrium in the above case, `'a'` moles of `CaCO_(3),'b'` moles of `CaO` and `'c'` moles of `CO_(2)` are found. Then, identify the wrong statement `:`
A
Moles of `CaCO_(3)` will decrease with the addition of inert gas at constant pressure
B
Moles of `CaCO_(3)` will remain constant with the increases in volume.
C
If volume of the vessel in halved, then moles of `CaCO_(3)` will increases
D
Moles of `CaO` will decreases with the increases in pressure.
For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..
The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when
For the reaction CaCO_(3)(s)hArrCaO(s)+CO_(2)(g) the equilibrium amount of CO_(2) can be increased by :
CaCO_3(s) hArr CaO(s) + CO_2(g), DeltaH =110 kJ The pressure of CO_2 :
CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) For the equilibrium , it is found that log K_(p)=8-(6400(K))/(T) T=527^(@)C if :
CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) in closed container at equilibrium. What would be the effect of addition of CaCO_(3) on the equilibrium concentration of CO_(2) .
