In the following reaction `:` `2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)` the equilibrium is not attained . The rate of forward reaction is greater than that of backward. Thus, which of the following is the correct relation between `K_(p)` and `Q_(p)` ?
A
`K_(p)=Q_(p)`
B
`Q_(p)gt K_(p)`
C
`Q_(p) lt K_(p)`
D
`K_(p) = Q_(p) =1`
Text Solution
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The correct Answer is:
3
As the rate of forward reaction is greater than that of backward reaction, the reaction must proceed in the forward direction. Hence, `Q_(p) lt K_(p)`.
Mass action rato or reaction quotient Q for a reaction can be calculate using the law of masss action A(g)+B(g) hArr C(g)+D(g) Q=([C][D])/([A][B]) The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q=K For an equilibrium process, Q ne K when Q gt K , reaction will favour backward direction and when Q lt K , it will favour direction. Answer the following questions: In the following reaction: 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g) the equilibrium is not attained. The rate of forward reaction is greater than that of backward reaction. Thus, which of the following is the correct relation between K_(p) and Q_(p) ?
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