`AB_(3)(g)` is dissociation as `AB_(2)(g) hArr AB_(2)(g)+(1)/(2)B_(2)(g)`, When the initial pressure of `AB_(2)` is 800 torr and the total pressure developed at equilibrium is 900 torr. What fraction of `AB_(3)(g)` is dissociated ?
AB_(3)(g) is dissociates as AB_(3)(g)hArrAB_(@)(g)+(1)/(2)B_(@)(g) When the initial pressure of AB_(3) is800 torr and the pressure developed at equilibrium is 900 torr , what fraction of AB_(3)(g) is dissociated?
AB_(2) dissociates as AB_(2)(g) hArr AB(g)+B(g) . If the initial pressure is 500 mm of Hg and the total pressure at equilibrium is 700 mm of Hg. Calculate K_(p) for the reaction.
A gaseous compound XY_2 dissociates as: XY_2(g) hArr XY(g) + Y(g) If the initial pressure is 500 mm of Hg and the total pressure at equilibrium is 700 mm of Hg, calculate K_p for the reaction.
XY_(2) dissociates XY_(2)(g) hArr XY(g)+Y(g) . When the initial pressure of XY_(2) is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.
PQ_(2) dissociates as PQ_2 (g)hArrPQ(g)+Q(g) The initial pressure of PQ_2 is 600 mm Hg. At equilibrium, the total pressure is 800mm Hg. Calculate the value of K_p .