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At a certain temperature the equilibrium...

At a certain temperature the equilibrium constant `K_(c)` is `0.25` for the reaction
`A_(2)(g)+B_(2)(g) hArr C_(2)(g)+D_(2)(g)`
If we take 1 mole of each of the four gases in a 10 litre container, what would be equlibrium concentration of `A_(2)(g)` ?

A

`0.331M`

B

`0.033M`

C

`0.133M`

D

`1.33M`

Text Solution

Verified by Experts

The correct Answer is:
3
`Q_(c)=(1xx1)/(1xx1)=1`
`:'Q_(c)gtK_(c)` sor reaction will proceed in backward direction `:`
`{:(,A_(2)(g),+,B_(2)(g),hArr,C_(2)(g),+,D_(2)(g)),("Conc. eqm",(1+x)/(10),,(1+x)/(10),,(1+x)/(10),,(1-x)/(10)):}`
`0.25=(((1-x)/(10))^(2))/(((1+x)/(10))^(2))" "rArr" "x=0.333`
`[A_(2)(g)]=(1+x)/(10)=(1.333)/(10)=0.133`
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