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At a certain temperature , the equilibr...

At a certain temperature , the equilibrium constant `(K_(c))` is `4//9` for the reaction `:`
`CO(g)+H_(2)O(g) hArr CO_(2)(g)+H_(2)(g)`
If we take 10 mole of each of the four gases in a one `-` litre container, what would be the equilibrium mole percent of `H_(2)(g)` ?

A

20

B

40

C

60

D

80

Text Solution

Verified by Experts

The correct Answer is:
1
We have,
`{:(10" mole",,10" mole",,10" mole",,10" mole","Initial moles"),(CO(g),+,H_(2)O(g),hArr,CO_(2)(g),+,H_(2)(g),),(10+x,,10+x,,10-x,,10-x,"Moles at eqb. or concentration at eqb."):}`
where x is the number of moles of each reactant changed to the products at equilibrium.
`K=((10-x)^(2))/((10+x)^(2))=4//9("given")" "or " "(10+x)/(10-x)=3//2,x=2`
Mole percent of `H_(2)(g)` at equilibrium `=(10-x)/(40)xx100=20`
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