Home
Class 11
CHEMISTRY
For A(g) hArr 2B(g), equilibrium constan...

For `A(g) hArr 2B(g)`, equilibrium constant at total equilibrium pressure `p_(1)` is
`K_(p1)& ` for `C(g)hArrD(g)+E(g)`.
equilibrium constant at total equilibrium pressure `p_(2)` is `K_(p2)`. If degree of dissciation of `A & C` are same, then the ratio `K_(p1) //K_(p2)` , if `2p_(1)=p_(2)`, is `:`

A

2

B

`1//8`

C

`1//2`

D

8

Text Solution

Verified by Experts

The correct Answer is:
1
`K_(p1)=(4alpha.^(2)P_(1))/(1-alpha^(2)),K_(p^(2))=(alpha^(2)P_(2))/(1-alpha^(2))rArr" "(K_(p_(1)))/(K_(p_(2)))=(4P_(1))/(P_(2))=4xx(1)/(2)=2`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    RESONANCE|Exercise Solved examples|9 Videos

  • CHEMICAL EQUILIBRIUM

    RESONANCE|Exercise (MSPs)|8 Videos

  • CHEMICAL BONDING

    RESONANCE|Exercise Inorganic chemistry (Chemistry Bonding)|49 Videos

  • D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS

    RESONANCE|Exercise Match the column|1 Videos

Similar Questions

Explore conceptually related problems

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) The equilibrium constant K_(p) changes with

The degree of dissociation of SO_(3) at equilibrium pressure is: K_(p) for 2SO_(3) (g)hArr2SO_(2)(g) + O_(2) (g)

The equilibrium constant K_p for the reaction AhArr2B is related to the degree of dissociation (alpha) of A and total pressure P as

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

In the equilibrium constant for AhArr B+C is K_(eq)^((1)) and that of B+C=P is K_(eq)^((2)) , the equilibrium constant for AhArr P is :

For the reaction N_(2)O_(4)(g)hArr2NO_(2)(g) , the degree of dissociation at equilibrium is 0.2 at 1 atm pressure. The equilibrium constant K_(p) will be

For the reaction N_(2)O_(4)(g) hArr 2NO_(2)(g) the degree of dissociation at equilibrium is 0.2 at 1 atmospheric pressure. The equilibrium constant K_(p) will be