Four solution of `NH_(4)Cl` are taken with concentration `1M,0.1M,0.01M & 0.001M`. Their degree of hydrolysis are `h_(1),h_(2) & h_(3),h_(4)`. What is the graduation of degree of hydrolysis ?

Options

A. `h_(1)gth_(2)gth_(3)gth_(4)`
B. `h_(1)=h_(2)=h_(3)=h_(4)`
C. `h_(4)gth_(3)gth_(2)gth_(1)`
D. None of these

Answer

3

Explanation

`NH_(4)Cl+H_(2)OhArrNH_(4)OH+HCl`
`k_(b)=(Ch^(2))/(1-h)" "k_(h)` is const
`1-h=1" "k_(h)=Ch^(2)rArrh=sqrt((k_(h))/(C))` as 3 increases h decreases
`:.` Answer is `(3)`