Calculate the `pH` of resulting solution obtained by mixing `50 mL` of `0.6N HCl` and `50 ml ` of `0.3 N NaOH`

Options

A. `0.1`
B. `0.8`
C. `2.1`
D. 4

Answer

2

Explanation

`{:(,HCl,+,NaOHrarrNaCl,,+,H_(2)O),("Meq. before reaction",50xx0.6=30,,50xx0.3=15,0,,0),("Meq.after reaction",15,,0,15,,15):}`
For monovalent electrolysis`" " `Molarity =Normality `=("milli equivalent")/("total volume")`
`[Cl^(-)` provided by HCl and NaCl]
`[H^(+)]=(15)/(100)=0.15M`,
Also `p-log[H^(+]-log 0.15," "pH =0.8239`