To a 10mL of 10^(-3) N H(2)SO(4) solutio...

To a `10mL` of `10^(-3) N H_(2)SO_(4)` solution water has been to make the total volume of one litre. Its `pOH` would be `:`

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The correct Answer is:

`N_(1)V_(1)=N_(2)V_(2)`
`10^(-3)xx10=N_(2)xx1000`
`rArrN_(2)=10^(-5)`
`:. pH=5`
and `pOH=14-5=9`

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