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10mL of a strong acid solution of pH=2....

`10mL` of a strong acid solution of `pH=2.000` are mixed with `990 mL` of another strong acid solution of `pH=4.000`. The `pH` of the resulting solution will be `:`

A

`4.002`

B

`4.000`

C

`4.200`

D

`3.7`

Text Solution

Verified by Experts

The correct Answer is:
4
`[H^(+)]` after mixing `=(10^(-2)xx10+10^(-4)xx990)/(1000)=(0.1+0.0990)/(1000)=(0.1990)/(1000)=1.99xx10^(-4)...pH=4-0.3=3.7`
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