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A reaction, which is second order,has a ...

A reaction, which is second order,has a rate constant of `0.002 L mol^(-1)s^(-1)`. If the initial cond. Of the reactant is `0.2M`. How long will it take for the concentration to become `0.0400M` ?

A

`1000s `

B

`400 s`

C

`200 s`

D

`10,000s`

Text Solution

Verified by Experts

The correct Answer is:
4
`(1)/(C_(1))=(1)/(C_(0))+KL`
`(1)/(0.04)=(1)/(0.02)+0.002xxt.`
`rArr" "25=5+0.002xxt`
`rArr" "t=(20)/(2xx10^(-3))=10,000sec.`
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